The vapour pressure of acetone at 20 o C is 185   torr . When 1 . 2   g of a non-volatile…

The vapour pressure of acetone at 20oC is 185 torr. When 1.2 g of a non-volatile substance was dissolved in 100 g of acetone at 20oC , its vapour pressure was 183 torr. The molar mass (g mol-1) of the substance is:
  1. 488
  2. 32
  3. 64
  4. 128

Solution

Δ P = 1 8 5 - 1 8 3 = 2 torr

MCH3-CO||-CH3=15×2+16+12=58 g/mol

ΔPP0=185-183185=2185=XB=1.2M1.2M+10058

1.2 M << 1 0 0 5 8

⇒   2 1 8 5 = 1.2 M × 5 8 1 0 0

M = 5 8 × 1.2 1 0 0 × 1 8 5 2

=64.3864 g/mol

Asked in: JEE Main 2015 (04 Apr)

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