The values of $x$ at the stationary points of $f(x)=x^3+3 x^2-2$ are

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Aicharya · Accepted Answer

Let $y=f(x)=x^3+3 x^2-2$ $\frac{d y}{d x}=3 x^2+6 x \Rightarrow \frac{d^2 y}{d x^2}=6 x+6$ For stationary points $\frac{d y}{d x}=0$ $\Rightarrow \quad 3 x(x+2)=0 \Rightarrow x=0,-2$

The values of \(x\) at the stationary points of \(f(x)=x^3+3 x^2-2\) are

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