The values of observed and calculated molecular weights of silver nitrate are $92.64$ and $170$ respectively…
The values of observed and calculated molecular weights of silver nitrate are $92.64$ and $170$ respectively. The degree of dissociation of silver nitrate is
$60 \%$
$83.5 \%$
$46.7 \%$
$60.23 \%$
Solution
i for $\mathrm{AgNO}_{3}=\frac{\text { Normal mol.wt }}{\text { Observed mol.wt. }}=1+\alpha$
$\alpha=\frac{170}{92.64}-1=0.835=83.5 \%$