The values of $x$ for which the inequality $\frac{8 x^2+16 x-51}{(2 x-3)(x+4)}>3$ holds, are
- $x \geq 4$
- $-4 \leq x \leq-3$
- $\frac{3}{2} < x < \frac{5}{2}$
- $x < -4$ or $x>\frac{5}{2}$ or $-3 < x < \frac{3}{2}$
Solution
Asked in: AP EAMCET 2017 (25 Apr Shift 1)