The values of $K_{P 1}$ and $K_{\mathrm{P} 2}$ for the reactions $\begin{aligned} & X \rightleftharpoons Y+Z…

The values of $K_{P 1}$ and $K_{\mathrm{P} 2}$ for the reactions $\begin{aligned} & X \rightleftharpoons Y+Z . \\ & A \rightleftharpoons 2 B . . \end{aligned}$ are in ratio of 9:1. If degree of dissociation of $X$ and $\mathrm{A}$ be equal, then total pressure at equilibrium (1) and (2) are in the ratio
  1. $1: 1$
  2. $3: 1$
  3. $1: 9$
  4. $36: 1$

Solution

$\begin{aligned} & \text { or } \frac{\mathrm{K}_{\mathrm{P}_1}}{\mathrm{~K}_{\mathrm{P}_2}}=\frac{\mathrm{P}}{4 \mathrm{P}^{\prime}} \quad \text { or } \quad \frac{9}{1}=\frac{\mathrm{P}}{4 \mathrm{P}^{\prime}} \\ & \text { or } \frac{\mathrm{P}^{\prime}}{\mathrm{P}}=36: 1 \end{aligned}$

Asked in: NEET 2008 (Mains)

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