The values of $K_{P 1}$ and $K_{\mathrm{P} 2}$ for the reactions $\begin{aligned} & X \rightleftharpoons Y+Z…
- $1: 1$
- $3: 1$
- $1: 9$
- $36: 1$
Solution
$\begin{aligned}
& \text { or } \frac{\mathrm{K}_{\mathrm{P}_1}}{\mathrm{~K}_{\mathrm{P}_2}}=\frac{\mathrm{P}}{4 \mathrm{P}^{\prime}} \quad \text { or } \quad \frac{9}{1}=\frac{\mathrm{P}}{4 \mathrm{P}^{\prime}} \\
& \text { or } \frac{\mathrm{P}^{\prime}}{\mathrm{P}}=36: 1
\end{aligned}$Asked in: NEET 2008 (Mains)