The values of ∫ - π 2 π 2 sin 2 ⁡ x 1 + 2 x d x is

The values of -π2π2sin2x1+2xdx is
  1. π4
  2. π8
  3. π2
  4. 4π

Solution

I= -π2π2sin2x1+2x dx   ...(i)

As abf(x)dx=abf(a+bx)dx

I=-π2π2sin2-x1+2-xdx

I= -π2π22xsin2x1+2xdx    ...(ii) 

By adding Equations (i) and (ii),

2I= -π2π21+2xsin2x1+2xdx

2I=20π2sin2xdx

I=0π2cos2xdx

2I= 0π2sin2x+cos2xdx

2I= 0π21 dx

I=π2×12=π4

Asked in: MHT CET Full Test 11

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