The value of \(x\) in \(\left(0, \frac{\pi}{2}\right)\) satisfying the equation \((\sin x)(\cos…
The value of \(x\) in \(\left(0, \frac{\pi}{2}\right)\) satisfying the equation \((\sin x)(\cos x)=\frac{1}{4}\) is
- \(\frac{\pi}{6}\)
- \(\frac{\pi}{3}\)
- \(\frac{\pi}{8}\)
- \(\frac{\pi}{12}\)
Solution
Given, \(\sin x \cos x=\frac{1}{4}\)
\(\begin{array}{llll}
\Rightarrow & \sin 2 x =\frac{1}{2} \Rightarrow 2 x=30^{\circ}, 150^{\circ} \\
\Rightarrow & x =15^{\circ}, 75^{\circ} \\
\text {or } & x =\frac{\pi}{12}, \frac{5 \pi}{12} \in\left(0, \frac{\pi}{2}\right)
\end{array}\)
Asked in: AP EAMCET 2020 (18 Sep Shift 1)
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