The value of the acceleration due to gravity is g 1 at a height h = R 2 ( R = radius of the earth) from the…

The value of the acceleration due to gravity is g1 at a height h=R2 (R= radius of the earth) from the surface of the earth. It is again equal to g1 at a depth d below the surface the earth. The ratio dR equals:
  1. 49
  2. 59
  3. 13
  4. 79

Solution

Given that

gn=gd

GM(R+h)2=GMR3(R-d)

GM(R+R/2)2=GMR3(R-d)

4GM9R2=GMR21-dR

49=1-dR

dR=1-49=59

d=59R

Asked in: JEE Main 2020 (05 Sep Shift 1)

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