The value of $k$, such that $\frac{x-4}{1}=\frac{y-2}{1}=\frac{z-k}{2}$ lies on the plane $2 x-4 y+z=7$, is
The value of $k$, such that $\frac{x-4}{1}=\frac{y-2}{1}=\frac{z-k}{2}$ lies on the plane $2 x-4 y+z=7$, is
no real value
4
-7
7
Solution
To lie the line on the plane, the point on the line must lie on the plane
$\begin{aligned}
& \Rightarrow 2 \times 4-4 \times 2+k=7 \\
& \Rightarrow k=7
\end{aligned}$