The value of ∑ r = 0 20 C 6 50 - r is equal to:

The value of r=020C650-r is equal to:
  1. C751-C730
  2. C750-C730 
  3. C650-C630 
  4. C751+C730 

Solution

r=020C650-r=

=50C6+49C6+48C6+....+30C6

=30C7+30C7+30C6+31C6+32C6+....+50C6

=30C7+31C7+31C6+32C6+....+50C6

=30C7+32C7+32C6+....+50C6

=30C7+51C7.

Asked in: JEE Main 2020 (04 Sep Shift 1)

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