The value of m such that $\frac{x-4}{1}=\frac{y-2}{1}=\frac{z+\mathrm{m}}{2}$ lies in the plane $2 x-4 y+z=7$ is

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Aicharya · Accepted Answer

Point $(4,2,-\mathrm{m})$ should lie in the plane $2 x-4 y+z=7$ $\begin{array}{ll} 	herefore \quad & 2(4)-4(2)-m=7 \ & \Rightarrow m=-7 \end{array}$

The value of m such that $\frac{x-4}{1}=\frac{y-2}{1}=\frac{z+\mathrm{m}}{2}$ lies in the plane $2 x-4…