The value of log 2 ⁡ 9 2 1 log 2 ⁡ log 2 ⁡ 9 × 7 1 log 4 ⁡ 7 is_____.

The value of log2⁡921log2⁡log2⁡9×71log4⁡7 is_____.

Solution

log2⁡92log2⁡log2⁡9×712log4⁡7
= ( log 2 9 ) 2 log ( log 2 9 ) 2 × 7 1 2 log 7 4
= ( log 2 9 ) log ( log 2 9 ) 2 2 × 7 log 7 4 1 2
= 2 2 × 4 1 2
=  4×2=8

Asked in: JEE Advanced 2018 (Paper 1)

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