The value of lim n → ∞ 1 n ∑ j = 1 n 2 j - 1 + 8 n 2 j - 1 + 4 n is equal to:

The value of limn1nj=1n2j-1+8n2j-1+4n is equal to:
  1. 5+loge32
  2. 2-loge23
  3. 3+2loge23
  4. 1+2loge32

Solution

limn1nj=1n2jn-1n+82jn-1n+4

012x+82x+4dx=01dx+0142x+4dx

=1+412ln2x+4|01

=1+2n32

Asked in: JEE Main 2021 (27 Jul Shift 1)

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