The value of $\int_{-1}^{1} |x - [x]| dx$ (where $[.]$ denotes greatest integer function) is
The value of $\int_{-1}^{1} |x - [x]| dx$ (where $[.]$ denotes greatest integer function) is
- 0
- 1
- 2
- None of these
Solution
$\int_{-1}^{1}(x-[x])dx = \int_{-1}^{1}xdx - \int_{-1}^{1}[x]dx$
$= \left[\frac{x^{2}}{2}\right]_{-1}^{1} - \left[\int_{-1}^{0}[x]dx + \int_{0}^{1}[x]dx\right]$
$= $\frac{1}{2}$[1 - (-1)] - \left[\int_{-1}^{0}(-1)dx + \int_{0}^{1}0dx\right]$
$\begin{aligned}
&\text{If } -1 \leq x < 0, [x] = -1\\
&\text{If } 0 \leq x < 1, [x] = 0
\end{aligned}$
$= 0 - [-x]_{-1}^{0} - 0 = 0 - [-0 - (-1)] = 1$
Asked in: MHT CET Full Test 3
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