The value of K C for the equilibrium reaction: CO 2 ( g ) + C ( s ) ⇌ 2 CO ( g ) at T ( K ) is 0 . 036…

The value of KC for the equilibrium reaction:
CO2(g)+C(s)⇌2CO(g)
at T(K) is 0.036. If the equilibrium concentration of CO2( g) is 0.004M, the concentration of CO(g) in molL-1 is
  1. 3.6×10-2
  2. 2.0×10-2
  3. 1.2×10-2
  4. 1.2×10-3

Solution

As equilibrium constant can be written as:

Kc=CO2CO20.036=CO20.004CO=1.2×10-2

Asked in: AP EAMCET 2019 (21 Apr Shift 2)

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