The value of electric potential at a distance of 9 cm from the point charge $4 \times 10^{-7} \mathrm{C}$ is…

The value of electric potential at a distance of 9 cm from the point charge $4 \times 10^{-7} \mathrm{C}$ is $\left[\right.$ Given $\left.\frac{1}{4 \pi \varepsilon_0}=9 \times 10^9 \mathrm{~N} \mathrm{~m}^2 \mathrm{C}^{-2}\right]$ :
  1. $4 \times 10^2 V$
  2. 44.4 V
  3. $4.4 \times 10^5 \mathrm{~V}$
  4. $4 \times 10^4 \mathrm{~V}$

Solution

$V=\frac{k q}{r}$ $=9 \times 10^9 \times \frac{4 \times 10^{-7}}{9 \times 10^{-2}}$ $=4 \times 10^4 \mathrm{~V}$

Asked in: NEET 2024 (Re-NEET)

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