The value of $\tan \left(2 \tan ^{-1}\left(\frac{\sqrt{5}-1}{2}\right)\right)$ is
The value of $\tan \left(2 \tan ^{-1}\left(\frac{\sqrt{5}-1}{2}\right)\right)$ is
- $2 \sqrt{5}$
- 4
- 2
- $\sqrt{5}-1$
Solution
$\begin{aligned} & \tan \left(2 \tan ^{-1}\left(\frac{\sqrt{5}-1}{2}\right)\right) \\ & =\frac{2 \tan \left(\tan ^{-1}\left(\frac{\sqrt{5}-1}{2}\right)\right)}{1-\tan ^2\left(\tan ^{-1}\left(\frac{\sqrt{5}-1}{2}\right)\right)} \\ & =\frac{2\left(\frac{\sqrt{5}-1}{2}\right)}{1-\left(\frac{\sqrt{5}-1}{2}\right)^2} \\ & =\frac{\sqrt{5}-1}{1-\left(\frac{6-2 \sqrt{5}}{4}\right)} \\ & =\frac{4(\sqrt{5}-1)}{2 \sqrt{5}-2} \\ & =\frac{4(\sqrt{5}-1)}{2(\sqrt{5}-1)}=2\end{aligned}$
Asked in: MHT CET 2024 (02 May Shift 2)
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