The value of $\tan ^{-1}(1)+\cos ^{-1}\left(-\frac{1}{2}\right)+\sin ^{-1}\left(-\frac{1}{2}\right)$ is

The value of $\tan ^{-1}(1)+\cos ^{-1}\left(-\frac{1}{2}\right)+\sin ^{-1}\left(-\frac{1}{2}\right)$ is
  1. $\frac{5 \pi}{6}$
  2. $\frac{\pi}{2}$
  3. $\frac{2 \pi}{3}$
  4. $\frac{3 \pi}{4}$

Solution

$\begin{aligned} & \tan ^{-1}(1)+\cos ^{-1}\left(\frac{-1}{2}\right)+\sin ^{-1}\left(\frac{-1}{2}\right) \\ & =\frac{\pi}{4}+\frac{2 \pi}{3}-\frac{\pi}{6} \\ & =\frac{3 \pi}{4}\end{aligned}$

Asked in: MHT CET 2023 (10 May Shift 2)

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