The value of $\tan ^{-1}(1)+\cos ^{-1}\left(-\frac{1}{2}\right)+\sin ^{-1}\left(-\frac{1}{2}\right)$ is
The value of $\tan ^{-1}(1)+\cos ^{-1}\left(-\frac{1}{2}\right)+\sin ^{-1}\left(-\frac{1}{2}\right)$ is
- $\frac{5 \pi}{6}$
- $\frac{\pi}{2}$
- $\frac{2 \pi}{3}$
- $\frac{3 \pi}{4}$
Solution
$\begin{aligned} & \tan ^{-1}(1)+\cos ^{-1}\left(\frac{-1}{2}\right)+\sin ^{-1}\left(\frac{-1}{2}\right) \\ & =\frac{\pi}{4}+\frac{2 \pi}{3}-\frac{\pi}{6} \\ & =\frac{3 \pi}{4}\end{aligned}$
Asked in: MHT CET 2023 (10 May Shift 2)
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