The value of $\tan ^{-1} 2+\tan ^{-1} 3$ is
The value of $\tan ^{-1} 2+\tan ^{-1} 3$ is
- $\left(\frac{3 \pi}{4}\right)^c$
- $\left(\frac{\pi}{2}\right)^c$
- $\left(\frac{\pi}{4}\right)^c$
- $\left(\frac{\pi}{6}\right)^c$
Solution
$\begin{aligned} & \tan ^{-1} 2+\tan ^{-1} 3 \\ & =\tan ^{-1}\left[\frac{2+3}{1-(2)(3)}\right]=\tan ^{-1}\left(\frac{5}{1-6}\right)=\tan ^{-1}(-1)=\left(\frac{3 \pi}{4}\right)^c\end{aligned}$
Asked in: MHT CET 2021 (24 Sep Shift 2)
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