The value of $\sum_{k=1}^{10}\left(\sin \frac{2 k \pi}{11}+i \cos \frac{2 k \pi}{11}\right)$ is
The value of $\sum_{k=1}^{10}\left(\sin \frac{2 k \pi}{11}+i \cos \frac{2 k \pi}{11}\right)$ is
i
1
-1
-i
Solution
$\sum_{k=1}^{10}\left(\sin \frac{2 k \pi}{11}+i \cos \frac{2 k \pi}{11}\right)=\sum_{k=1}^{10} \sin \frac{2 k \pi}{11}+i \sum_{k=1}^{10} \cos \frac{2 k \pi}{11}$
$=0+i(-1)=-i$