The value of $\sin ^{-1}\left(\frac{-1}{2}\right)+\sin ^{-1}\left(\frac{-\sqrt{3}}{2}\right)$ is

The value of $\sin ^{-1}\left(\frac{-1}{2}\right)+\sin ^{-1}\left(\frac{-\sqrt{3}}{2}\right)$ is
  1. $\frac{\pi}{3}$
  2. $\frac{-\pi}{6}$
  3. $\frac{-\pi}{3}$
  4. $\frac{-\pi}{2}$

Solution

$\sin ^{-1}\left(\frac{-1}{2}\right)+\sin ^{-1}\left(\frac{-\sqrt{3}}{2}\right)=\frac{-\pi}{3}-\frac{\pi}{6}=\frac{-\pi}{2}$

Asked in: MHT CET 2021 (23 Sep Shift 1)

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