The value of $\mathrm{k}$ such that $\frac{x-4}{1}=\frac{y-2}{1}=\frac{z-k}{2}$ lies in the plane $2 x-4…
The value of $\mathrm{k}$ such that $\frac{x-4}{1}=\frac{y-2}{1}=\frac{z-k}{2}$ lies in the plane $2 x-4 y+z=7$, is
No real value
4
7
-7
Solution
$\because 2 \times 1-4 \times 1+1 \times 2=0$ i.e. line is parallel to the plane now $2 \times 4-4 \times 2+K=7$ (for having a common point) $\Rightarrow K=7$