The value of $\int_{-\pi}^\pi \frac{\cos ^2 x}{1+a^x} d x, a>0$, is
The value of $\int_{-\pi}^\pi \frac{\cos ^2 x}{1+a^x} d x, a>0$, is
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$a \pi$
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$\frac{\pi}{2}$
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$\frac{\pi}{a}$
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$2 \pi$
Solution
$
\int_{-\pi}^\pi \frac{\cos ^2 x}{1+a^x} d x=\int_0^\pi \cos ^2 x d x=\frac{\pi}{2} .
$
Asked in: JEE Main 2005
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