The value of $\cos 20^{\circ}+2 \sin ^2 55^{\circ}-\sqrt{2} \sin 65^{\circ}$ is
The value of $\cos 20^{\circ}+2 \sin ^2 55^{\circ}-\sqrt{2} \sin 65^{\circ}$ is
- 0
- 1
- -1
- $\frac{1}{2}$
Solution
$\begin{aligned} & \cos 20^{\circ}+2 \sin ^2 55^{\circ}-\sqrt{2} \sin 65^{\circ} \\ & =\cos 20^{\circ}+1-\cos 2\left(55^{\circ}\right)-\sqrt{2} \sin 65^{\circ} \\ & \ldots\left[2 \sin ^2 \theta=1-\cos 2 \theta\right] \\ & =\cos 20^{\circ}-\cos 110^{\circ}-\sqrt{2} \sin 65^{\circ}+1 \\ & =2 \sin 65^{\circ} \sin 45^{\circ}-\sqrt{2} \sin 65^{\circ}+1 \\ & =2 \sin 65^{\circ}\left(\frac{1}{\sqrt{2}}\right)-\sqrt{2} \sin 65^{\circ}+1 \\ & =\sqrt{2} \sin 65^{\circ}-\sqrt{2} \sin 65^{\circ}+1 \\ & =1\end{aligned}$
Asked in: MHT CET 2024 (16 May Shift 2)
Practice more Trigonometric Ratios & Identities questions on Aicharya