The value of $\cos ^{-1}\left(\cos \left(\frac{7 \pi}{6}\right)\right)$ is
- $\frac{5 \pi}{6}$
- $\frac{\pi}{3}$
- $\frac{7 \pi}{6}$
- $\frac{\pi}{6}$
Solution
\(\begin{aligned}
& =\cos ^{-1}\left[\cos \left(2 \pi-\frac{5 \pi}{6}\right)\right] \\
& =\cos ^{-1}\left(\cos \frac{5 \pi}{6}\right) \\
& =\frac{5 \pi}{6}
\end{aligned}\)
Asked in: MHT CET 2020 (19 Oct Shift 1)
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