The value of $4 \cos ^3 20^{\circ}$ is
The value of $4 \cos ^3 20^{\circ}$ is
- $-\frac{1}{2}-\cos 20^{\circ}$
- $-\frac{1}{2}+3 \cos 20^{\circ}$
- $\frac{1}{2}+3 \cos 20^{\circ}$
- $\frac{1}{2}-3 \cos 20^{\circ}$
Solution
$\begin{aligned} & 4 \cos ^3 20^{\circ}=\cos \left(3 \times 20^{\circ}\right)+3 \cos 20^{\circ}\left[\because 4 \cos ^3 \theta=\cos 3 \theta+3 \cos \theta\right] \\ & \Rightarrow 4 \cos ^3 20^{\circ}=\cos 60^{\circ}+3 \cos 20^{\circ}=\frac{1}{2}+3 \cos 20^{\circ}\end{aligned}$
Asked in: MHT CET 2022 (07 Aug Shift 2)
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