The value of $2 \tan ^{-1} \frac{1}{2}+\tan ^{-1} \frac{1}{7}$
The value of $2 \tan ^{-1} \frac{1}{2}+\tan ^{-1} \frac{1}{7}$
- $\tan ^{-1}\left(\frac{17}{31}\right)$
- $\tan ^{-1}\left(\frac{19}{31}\right)$
- $\tan ^{-1}\left(\frac{31}{17}\right)$
- $\tan ^{-1}\left(\frac{31}{19}\right)$
Solution
$\begin{aligned} & 2 \tan ^{-1} \frac{1}{2}+\tan ^{-1} \frac{1}{7} \\ & =\tan ^{-1}\left(\frac{2\left(\frac{1}{2}\right)}{1-\left(\frac{1}{2}\right)^2}\right)+\tan ^{-1}\left(\frac{1}{7}\right) \\ & =\tan ^{-1}\left(\frac{4}{3}\right)+\tan ^{-1}\left(\frac{1}{7}\right) \\ & =\tan ^{-1}\left(\frac{\frac{4}{3}+\frac{1}{7}}{1-\left(\frac{4}{3}\right)\left(\frac{1}{7}\right)}\right) \\ & =\tan ^{-1}\left(\frac{31}{17}\right)\end{aligned}$
Asked in: MHT CET 2023 (11 May Shift 1)
Practice more Inverse Trigonometric Functions questions on Aicharya