The value of  b + c a a b c + a b c c a + b  is 

 The value of b+caabc+abcca+b is 
  1. abc
  2. (a+b)(b+c)(c+a)
  3. 4abc
  4. (ab)(bc)(ca)

Solution

Let =b+caabc+abcca+b.

Applying R1R1+R2+R3

=b+c+b+ca+c+a+ca+b+a+bbc+abcca+b

=2b+c2a+c2a+bbc+abcca+b

=2b+ca+ca+bbc+abcca+b

Applying R1R1-R2

=2b+c-ba+c-(c+a)a+b-bbc+abcca+b

=2c0abc+abcca+b

Applying R3R3-R1

=2c0abc+ab0cb

Applying R2R2-R3

=2c0aba00cb

=2cab-0-0+abc-0

=2abc+abc

=4abc.

Asked in: AP EAMCET 2021 (19 Aug Shift 2)

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