Mathematics › Determinants › Expansion of Determinants
Let △=b+caabc+abcca+b.
Applying R1→R1+R2+R3
△=b+c+b+ca+c+a+ca+b+a+bbc+abcca+b
⇒△=2b+c2a+c2a+bbc+abcca+b
⇒△=2b+ca+ca+bbc+abcca+b
Applying R1→R1-R2
⇒△=2b+c-ba+c-(c+a)a+b-bbc+abcca+b
⇒△=2c0abc+abcca+b
Applying R3→R3-R1
⇒△=2c0abc+ab0cb
Applying R2→R2-R3
⇒△=2c0aba00cb
⇒△=2cab-0-0+abc-0
⇒△=2abc+abc
⇒△=4abc.
Asked in: AP EAMCET 2021 (19 Aug Shift 2)
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