The value of ( a → × b → ) 2 + ( a → · b → ) 2 2 ( a → ) 2 ( b…

The value of (a×b)2+(a·b)22(a)2(b)2 is
  1. 0
  2. 1
  3. 12
  4. 14

Solution

Given, (a×b)2+(a·b)22(a)2(b)2

We know, (a)2=a·a=a2, (a×b)2=a2b2sin2θ, (a·b)2=a2b2cos2θ

Where, a=a, b=b

=a2b2sin2θ+a2b2cos2θ2a2b2

=a2b2(sin2θ+cos2θ)2a2b2

=12

Asked in: AP EAMCET 2021 (20 Aug Shift 2)

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