Mathematics › Vectors › Product of 2 vectors
Given, (a→×b→)2+(a→·b→)22(a→)2(b→)2
We know, (a→)2=a→·a→=a2, (a→×b→)2=a2b2sin2θ, (a→·b→)2=a2b2cos2θ
Where, a→=a, b→=b
=a2b2sin2θ+a2b2cos2θ2a2b2
=a2b2(sin2θ+cos2θ)2a2b2
=12
Asked in: AP EAMCET 2021 (20 Aug Shift 2)
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