The value of ∫ - π / 2 π / 2 d x x + sin ⁡ x   +   4 , where t denotes the…

The value of -π/2π/2dxx+sinx + 4, where t denotes the greatest integer less than or equal to t, is
  1. 3204π-3
  2. 3104π-3
  3. 1127π-5
  4. 1127π+5

Solution

We have-π2π2dx[x]+[sinx]+4

=-π20dx[x]+3+0π2dx[x]+4

=-π2-1dx1+-10dx2+01dx4+1π2dx5

=[x]-π2-1+x2-10+x401+x51π2=-1+π2+0+12+14+π10-15

=-20+10π+10+5+2π-420=12π-920=3204π-3

Asked in: JEE Main 2019 (10 Jan Shift 2)

Practice more Definite Integration questions on Aicharya