The value of ∫ - 2 2 3 x 2 - 3 x - 6 d x is

The value of -223x2-3x-6dx is

Solution

-223x2-x-2dx

=3-22x2-x-2dx

=3-2-1x2-x-2dx+-12-x2-x-2dx

=3x33-x22-2x-2-1-x33-x22-2x-12

=37-23

=19

Asked in: JEE Main 2021 (25 Feb Shift 2)

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