The value of ∫ - 1 1 x 2 e x 3 d x , where t denotes the greatest integer ≤ t , is :

The value of -11x2ex3dx, where t denotes the greatest integer t, is :
  1. e+13
  2. e-13e
  3. 13e
  4. e+13e

Solution

I=-11x2ex3dx

=-10x2ex3dx+01x2ex3dx

=-10x2e-1dx+01x2e0dx

=1e×x330-1+x3301

=1e×0--13+13

=13e+13=1+e3e

Asked in: JEE Main 2021 (25 Feb Shift 1)

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