The value of 0 . 16 log 2 . 5 1 3 + 1 3 2 + 1 3 3 + … . ∞ is __________

The value of 0.16log2.513+132+133+….∞ is __________

Solution

0.16log2.513+132+133+….∞

=0.16log2.5131-13=425log5212

=52-2log5212=12-2=4

Asked in: JEE Main 2020 (03 Sep Shift 1)

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