The value of ∫ 0 1 4 x 3 d 2 d x 2 1 - x 2 5 d x is ____________

The value of 014x3d2dx21-x25dx is ____________

Solution

014x3d2dx2 1-x25dx
=4x3ddx 1-x2501- 0112x2ddx 1-x25 dx
=4x3 ×51-x24 -2x01-12x21-x2501- 012x1-x25dx
=0-0-120-0+12 012x1-x25 dx
=12 ×-1-x26601
=120+16=2

Asked in: JEE Advanced 2014 (Paper 1)

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