The upper half of an inclined plane with inclination $\phi$ is perfectly smooth while the lower half is…
The upper half of an inclined plane with inclination $\phi$ is perfectly smooth while the lower half is rough. A body starting from rest at the top will again come to rest at the bottom if the coefficient of friction for the lower half is given by
$2 \sin \phi$
$2 \cos \phi$
$2 \tan \phi$
$\tan \phi$
Solution
$m g s \sin \phi=\mu m g \cos \phi \cdot \frac{s}{2}$