The unit of $\sqrt{\frac{2 \mathrm{I}}{\epsilon_0 c}}$ is : (I = intensity of an electromagnetic wave,…

The unit of $\sqrt{\frac{2 \mathrm{I}}{\epsilon_0 c}}$ is :
(I = intensity of an electromagnetic wave, $\mathrm{c}:$ speed of light)
  1. Vm
  2. NC
  3. Nm
  4. $\mathrm{NC}^{-1}$

Solution

$\begin{aligned}
& \mathrm{I}=\frac{1}{2} \epsilon_0 \mathrm{E}_0^2 \times \mathrm{C} \\ & \mathrm{E}_0=\sqrt{\frac{2 \mathrm{I}}{\epsilon_0 \mathrm{C}}}
\end{aligned}$
$E_0$ : electric field N/C

Asked in: JEE Main 2025 (07 Apr Shift 2)

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