The type of hybridization and the magnetic property of $\left[\mathrm{MnCl}_6\right]^{3-}$ are :

The type of hybridization and the magnetic property of $\left[\mathrm{MnCl}_6\right]^{3-}$ are :
  1. $d^2 s p^3$, paramagnetic with four unpaired electrons
  2. $\mathrm{sp}^3 \mathrm{~d}^2$, paramagnetic with four unpaired electrons
  3. $\mathrm{d}^2 \mathrm{sp}^3$, paramagnetic with two unpaired electrons
  4. $\mathrm{sp}^3 \mathrm{~d}^2$, paramagnetic with two unpaired electrons

Solution

$\begin{aligned} & {\left[\mathrm{MnCl}_6\right]^{3-} \text { contains } \mathrm{Mn}^{+3}} \\ & \mathrm{Mn}^{+3}:-[\mathrm{Ar}] 3 \mathrm{~d}^4 \\ & \text { Ligand } \Rightarrow \mathrm{Cl}^{-}(\mathrm{WFL})\end{aligned}$

$\text { Hybridisation }=\mathrm{sp}^3 \mathrm{~d}^2$
4 unpaired electrons

Asked in: JEE Main 2025 (02 Apr Shift 2)

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