The two ends of a rod of length $L$ and a uniform cross-sectional area $A$ are kept at two temperatures $\mathrm{T}_1$ and $\mathrm{T}_2\left(\mathrm{~T}_1 \mathrm{T}_2\right)$. The rate of heat transfer, $\frac{\mathrm{dQ}}{\mathrm{dt}}$, through the rod in a steady state is given by

Question

The two ends of a rod of length $L$ and a uniform cross-sectional area $A$ are kept at two temperatures $\mathrm{T}_1$ and $\mathrm{T}_2\left(\mathrm{~T}_1 > \mathrm{T}_2\right)$. The rate of heat transfer, $\frac{\mathrm{dQ}}{\mathrm{dt}}$, through the rod in a steady state is given by

Aicharya · Accepted Answer

For a rod of length $L$ and area of cross-section $A$ whose faces are maintained at temperature $\mathrm{T}_1$ and $\mathrm{T}_2$ respectively. Then in steady state the rate of heat flowing from one face to the other face in time $t$ is given by $\frac{\mathrm{dQ}}{\mathrm{dt}}=\frac{\mathrm{KA}\left(\mathrm{T}_1-\mathrm{T}_2\right)}{\mathrm{L}}$ The curved surface of rod is kept insulated from surrounding to avoid leakage of heat. .

The two ends of a rod of length $L$ and a uniform cross-sectional area $A$ are kept at two temperatures…

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