The truth table for the circuit given in the figure is:

The truth table for the circuit given in the figure is:
  1. $\begin{aligned} \begin{array}{|c c c|} \hline A & B & Y \\ \hline 0 & 0 & 0 \\ 0 & 1 & 0 \\ 1 & 0 & 1 \\ 1 & 1 & 1 \\ \hline \end{array} \end{aligned}$
  2. $\begin{aligned} &\begin{array}{|c c c|} \hline A & B & Y \\ \hline 0 & 0 & 1 \\ 0 & 1 & 0 \\ 1 & 0 & 0 \\ 1 & 1 & 0 \\ \hline \end{array} \end{aligned}$
  3. $\begin{aligned} \begin{array}{|c c c|} A & B & Y \\ 0 & 0 & 1 \\ 0 & 1 & 1 \\ 1 & 0 & 1 \\ 1 & 1 & 1 \\ \end{array} \end{aligned}$
  4. $\begin{aligned} \begin{array}{|c c c|} A & B & Y \\ 0 & 0 & 1 \\ 0 & 1 & 1 \\ 1 & 0 & 0 \\ 1 & 1 & 0 \\ \end{array} \end{aligned}$

Solution

$C = A + B$ and $y = \overline{A.C}$ $\begin{aligned} \begin{array}{ccccc} A & B & C = (A + B) & A.C & y = \overline{A.C} \\ 0 & 0 & 0 & 0 & 1 \\ 0 & 1 & 1 & 0 & 1 \\ 1 & 0 & 1 & 1 & 0 \\ 1 & 1 & 1 & 1 & 0 \\ \end{array} \end{aligned}$

Asked in: JEE Main 2019 (12 Apr Shift 1)

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