The treatment of $\mathrm{CH}_3 \mathrm{MgX}$ with $\mathrm{CH}_3 \mathrm{C} \equiv \mathrm{C}-\mathrm{H}$…
The treatment of $\mathrm{CH}_3 \mathrm{MgX}$ with $\mathrm{CH}_3 \mathrm{C} \equiv \mathrm{C}-\mathrm{H}$ produces
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$$
\mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}_2
$$
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Solution
$\mathrm{CH}_3-\mathrm{MgX}+\mathrm{CH}_3-\mathrm{C} \equiv \mathrm{C}-\mathrm{H} \longrightarrow \mathrm{CH}_4$
Asked in: JEE Main 2008
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