The treatment of \(\mathrm{Mg}_{3} \mathrm{~B}_{2}\) with acids produces
- \(\mathrm{B}_{2} \mathrm{O}_{3}\)
- \(\mathrm{MgB}_{2} \mathrm{O}_{4}\)
- \(\mathrm{B}_{4} \mathrm{H}_{10}\)
- \(\mathrm{MgB}_{4} \mathrm{O}_{7}\)
Solution
Asked in: JEE-TOPICTESTS-CHEMISTRY
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