with $\mathrm{NaIO}_{4}$ or boiling $\mathrm{KMnO}_{4}$ produces
The treatment of with $\mathrm{NaIO}_{4}$ or boiling $\mathrm{KMnO}_{4}$ produces
with $\mathrm{NaIO}_{4}$ or boiling $\mathrm{KMnO}_{4}$ produces
- $\mathrm{CH}_{3} \mathrm{COCH}_{3}$ and $\mathrm{CH}_{3} \mathrm{COOH}$
- $\mathrm{CH}_{3} \mathrm{COCH}_{3}$ and $\mathrm{HCHO}$
- $\mathrm{CH}_{3} \mathrm{CHO}$ and $\mathrm{CO}_{2}$
- $\mathrm{CH}_{3} \mathrm{COCH}_{3}$ only
Asked in: JEE-TOPICTESTS-CHEMISTRY