The treatment of an ester with $\mathrm{LiAlH}_{4}$ followed by acid hydrolysis produces
The treatment of an ester with $\mathrm{LiAlH}_{4}$ followed by acid hydrolysis produces
two alcohols
two acids
two aldehydes
one molecule of alcohol and another of carboxylic acid
Solution
Two alcohols are produced. $\mathrm{RCOOR}^{\prime} \stackrel{\mathrm{LiAlH}_{4}}{\longrightarrow} \mathrm{RCH}_{2} \mathrm{OH}+\mathrm{R}^{\prime} \mathrm{OH}$.