The translational kinetic energy of the molecules of a gas at absolute temperature $T$ can be doubled by

The translational kinetic energy of the molecules of a gas at absolute temperature $T$ can be doubled by
  1. decreasing $T$ to $\frac{T}{2}$
  2. increasing $T$ to $4 T$
  3. increasing $T$ to $\sqrt{2} T$
  4. increasing $T$ to $2 T$

Solution

The average translational kinetic energy $K$ is proportional to $T$. So, to double the $K$, temperature has to be doubled. *

Asked in: MHT CET 2022 (10 Aug Shift 1)

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