The translational kinetic energy of the molecules of a gas at absolute temperature ( $\mathrm{T}$ ) can be…

The translational kinetic energy of the molecules of a gas at absolute temperature ( $\mathrm{T}$ ) can be doubled
  1. by increasing $\mathrm{T}$ to $4 \mathrm{~T}$
  2. by increasing $\mathrm{T}$ to $2 \mathrm{~T}$
  3. by decreasing $\mathrm{T}$ to $\mathrm{T} / 2$
  4. by increasing $\mathrm{T}$ to $\sqrt{2} \mathrm{~T}$

Solution

$\mathrm{E}_{\text {molecule }}=\frac{3}{2} \mathrm{kT}$ Kinetic energy is directly proportional to absolute temperature.

Asked in: MHT CET 2021 (22 Sep Shift 1)

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