The transition metal in which of the following compound has zero oxidation state.
The transition metal in which of the following compound has zero oxidation state.
- $\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7$
- $\mathrm{KMnO}_4$
- $\mathrm{CrO}_5$
- $\mathrm{Fe}(\mathrm{CO})_5$
Solution
Oxidation states of given transition metals are as follows
\begin{array}{|c|c|c|}
\hline S.No. & Compound & Oxidation state of metal \\
\hline \multirow[t]{4}{*}{1.} & \mathrm{~K}_2 \mathrm{Cr}_2 \mathrm{O}_7 & \begin{array}{l}
2(+1)+2(x)+7(-2)=0 \\
x=+6
\end{array} \\
\hline & & i.e. \mathrm{Cr}=+6 \\
\hline & & Here, oxidation state of \mathrm{K}=1 \\
\hline & & Oxidation state of \mathrm{O}=-2 \\
\hline \multirow[t]{3}{*}{2.} & \mathrm{KMnO}_4 & 1+x+(-8)=0 \\
\hline & & x=+7 i.e. M n=+7 \\
\hline & & Here, oxidation state of \mathrm{K}=1 \\
\hline \multirow[t]{2}{*}{3.} & \mathrm{CrO}_5 & x+5(-2)=0 \\
\hline & & x=+10 i.e. \mathrm{Cr}=+10 \\
\hline \multirow[t]{3}{*}{4.} & \mathrm{Fe}(\mathrm{CO})_5 & x+5(0)=0 \\
\hline & & x=0 i.e. \mathrm{Fe}=0 \\
\hline & & \begin{array}{l}
Here, \mathrm{CO} is a neutral ligand \\
thus \mathrm{Fe} is having oxidation \\
number =0
\end{array} \\
\hline
\end{array}
Hence, only $\mathrm{Fe}(\mathrm{CO})_5$ has zero oxidation state.
Asked in: AP EAMCET 2021 (25 Aug Shift 1)
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