The trajectory of a projectile near the surface of the earth is given as y = 2 x - 9 x 2 . If it were…

1. ${\mathrm{\theta }}_0={\cos }^{-1}\left(\frac{1}{\sqrt{5}}\right)$ and $v_0=\frac{5}{3}\mathrm{ }\mathrm{m}{\mathrm{s}}^{-1}$
2. ${\mathrm{\theta }}_0={\cos }^{-1}\left(\frac{2}{\sqrt{5}}\right)$ and $v_0=\frac{3}{5}\mathrm{ }\mathrm{m}{\mathrm{s}}^{-1}$
3. ${\mathrm{\theta }}_0={\sin }^{-1}\left(\frac{1}{\sqrt{5}}\right)$ and $v_0=\frac{5}{3}\mathrm{ }\mathrm{m}{\mathrm{s}}^{-1}$
4. ${\mathrm{\theta }}_0={\sin }^{-1}\left(\frac{2}{\sqrt{5}}\right)$ and $v_0=\frac{3}{5}\mathrm{ }\mathrm{m}{\mathrm{s}}^{-1}$

Solution

Asked in: JEE Main 2019 (12 Apr Shift 1)

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