The total power dissipated in watt in the circuit shown here is:

The total power dissipated in watt in the circuit shown here is:
  1. 40
  2. 54
  3. 4
  4. 16

Solution

Total power dissipated $=\frac{V^2}{R}$
Power $=\frac{18 \times 18}{6}=54 \mathrm{~W}$

Asked in: NEET 2007

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