The total number of optically active compounds formed in the following reaction is:

The total number of optically active compounds formed in the following reaction is:

1. Zero
2. Six
3. Four
4. Two

Solution

The total number of optically active compounds formed is four. The product has two chiral $\mathrm{C}$ atoms. Thus, it has $2^n=2^2=4$ stereoisomers.

Asked in: JEE Main 2018 (15 Apr Shift 2 Online)

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