The total number of isomers for a square planar complex: MCl F NO 2 SCN is:

Question

Aicharya · Accepted Answer

Possible Structural isomers No of geometrical isomer by each MCl F NO 2 SCN 3 MCl F ONO SCN 3 MCl F NO 2 NCS 3 MCl F ONO NCS 3 Total number of isomers will be 12 .

Possible Structural isomers	No of geometrical isomer by each
$[MCl (F) ({NO}_{2}) (SCN)]$	$3$
$[MCl (F) (ONO) (SCN)]$	$3$
$[MCl (F) ({NO}_{2}) (NCS)]$	$3$
$[MCl (F) (ONO) (NCS)]$	$3$

The total number of isomers for a square planar complex: MCl F NO 2 SCN is:

Solution